Question

A hammer weighing 3 kg, moving with a velocity of 10 m/s, strikes against the head of a spike and drives it into a block of wood. If the hammer comes to rest in 0.025 s, the average (retarding) force acting on the spike will be

• A. 600 N
• B. -600 N
• C. 1200 N
• D. -1200 N

Answer 1

The correct option is D -1200 N

$F=\frac{mv-mu}{t}$

$Here,m=3kg,v=0,u=10m/s,t=0.025s$

So, $F=\frac{0-(3\times 10)}{0.025}=-1200N$