A hammer weighing 3 kg, moving with a velocity of 10 m/s, strikes against the head of a spike and drives it into a block of wood. If the hammer comes to rest in 0.025 s, the impulse associated with the spike will be :
A
30 Ns
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B
-30 Ns
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C
15 Ns
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D
-15 Ns
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Solution
The correct option is A 30 Ns
Initial momentum of the hammer Pi=mu=3×10=30kgm/s
Final momentum of the hammer Pf=0
Change in momentum of hammer ΔP=Pf−Pi=0−30=−30kgm/s