A hanging body of mass $m_{1}$ is pulled by a force F = $m_{2}$ g acting on the massless inextensible smooth string. The acceleration of $m_{1}$ is:

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Solution

The correct option is B

Here T = F = $m_{2}$ g

Now Free Body Diagram of block $m_{1}$

T - $m_{1}$ g = $m_{1}$ a

( $m_{2}$ g - $m_{1}$ g) = $m_{1}$ a

$a = \frac{(m_{2} - m_{1})}{m_{1}} g$

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A hanging body of mass m1 is pulled by a force F = m2 g acting on the massless inextensible smooth string. The acceleration of m1 is:

The correct option is B Here T = F = m2g Now Free Body Diagram of block m1 T - m1g = m1a (m2g - m1g) = m1a a=(m2−m1)m1g

A hanging body of mass $m_{1}$ is pulled by a force F = $m_{2}$ g acting on the massless inextensible smooth string. The acceleration of $m_{1}$ is:

The correct option is B

Here T = F = $m_{2}$ g

Now Free Body Diagram of block $m_{1}$

T - $m_{1}$ g = $m_{1}$ a

( $m_{2}$ g - $m_{1}$ g) = $m_{1}$ a

$a = \frac{(m_{2} - m_{1})}{m_{1}} g$