Question

A haunched reinforced concrete beam is simply supported at both ends as shown in figure. The beam is subjected to a uniformly distributed factored load of 15 kN/m. The design shear force at section X-X of beam is ____ kN. [Take effective cover as 50 mm throughout the beam]

• A. 120

Answer 1

The correct option is A 120
Shear force at section X-X $=\frac{24\times 15}{2}-15\times 6=90kN$

Depth of section X-X
$D=400+\frac{200}{12}\times 6=500mm$

d = 500 - 50 = 450 mm

Moment at section X-X
$M_u=180\times 6-\frac{15\times 6\times 6}{2}=810kNm$

$\therefore$ Design shear force at section X-X
$=V_u+\frac{M_u}{d}tan\beta =90+\frac{810}{0.45}\times \frac{200}{12000}\therefore V_{u,design}=120kN$