A hawk of mass 10 kg dives to catch a mouse. During dive it loses 500 J of its potential energy. The height from where it begins its dive is (take g = 10 m/s²)

1 m

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5 m

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50 m

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10 m

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Solution

The correct option is B
5 m

Change in Gravitational Potential Energy = mass x acceleration x change in height

500 J = 10 kg x 10 x change in height

Change in height = 5 m

So, the hawk dives to catch the mouse at a distance of 5m.

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A hawk of mass 10 kg dives to catch a mouse. During dive it loses 500 J of its potential energy. The height from where it begins its dive is (take g = 10 m/s2)

The correct option is B 5 m Change in Gravitational Potential Energy = mass x acceleration x change in height 500 J = 10 kg x 10 x change in height Change in height = 5 m So, the hawk dives to catch the mouse at a distance of 5m.

A hawk of mass 10 kg dives to catch a mouse. During dive it loses 500 J of its potential energy. The height from where it begins its dive is (take g = 10 m/s²)

The correct option is B
5 m

Change in Gravitational Potential Energy = mass x acceleration x change in height

500 J = 10 kg x 10 x change in height

Change in height = 5 m

So, the hawk dives to catch the mouse at a distance of 5m.