A hawker sells orange at a profit of $25 %$ . If he reduces the selling price of each orange by $60$ paise, he earns a profit of $5 %$ . Find the final selling price of each orange.

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Solution

Let CP = $x$ paise
Initial SP $= x + 25 % o f x = 1.25 x$

New SP $= (1.25 x - 60)$ paise
New gain $= 5 % o f x$
$\Rightarrow N e w S P - C P = 0.05 x$
$\Rightarrow 1.25 x - 60 - x = 0.05 x$
$\Rightarrow 0.25 x - 60 = 0.05 x$
$\Rightarrow 0.25 x - 0.05 x = 60$
$\Rightarrow 0.2 x = 60$
$\Rightarrow x = \frac{60}{0.2} = 300$

So, the CP $= 300 p a i s e$

Hence, final selling price
$= 1.25 x - 60$
$= (1.25 \times 300 - 60) p a i s e = 315 p a i s e = R s . 3.15$

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