Question

A heap of coconuts is divided into groups of $2,3$ and $5$ and each time one coconut is left over. The least number of coconuts in the heap is,

• A. $11$
• B. $21$
• C. $31$
• D. $41$

Answer 1

The correct option is C $31$

We know that the least number which when divided by $x,y,z$ leaves the same remainder R in each case is given by LCM of $(x,y,z)+R$
LCM of $(2,3,5)=30$
The least number of coconut in the heap is $30+1=31$