A heap of rice in the form of a cone of diameter 9 m and height 3.5 m. Find the volume of rice.How much canvas cloth is required to cover the heap?

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Solution

Volume of cone = $\frac{1}{3}$ × $π$ × $r^{2}$ × h

D = 9 m , r = 4.5 m

Volume = $\frac{1}{3}$ × $\frac{22}{7}$ × $\frac{9}{2}$ × $\frac{9}{2}$ × (3.5) = 74.25 m^3

Just to cover the heap, we need the CSA of cone

Slant height of cone = $\sqrt{r^{2} + h^{2}}$ = $\sqrt{{4.5}^{2} + {3.5}^{2}}$ = 5.7008 m

CSA= $π$ × r × l = $\frac{22}{7}$ × $\frac{9}{2}$ × (5.7008) = 80.6256 m

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A heap of rice in the form of a cone of diameter 9 m and height 3.5 m. Find the volume of rice.How much canvas cloth is required to cover the heap?

Volume of cone = 13 × π×r2× h D = 9 m , r = 4.5 m Volume = 13 × 227 × 92 × 92 × (3.5) = 74.25 m^3 Just to cover the heap, we need the CSA of cone Slant height of cone = √r2+h2 = √4.52+3.52 = 5.7008 m CSA= π × r × l = 227 × 92 × (5.7008) = 80.6256 m