A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3m. And its volume . The heap is to be covered by canvas to protect it from rain . Find the area of the canvas required.

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Solution

i ) volume of the heap = volume of the cone

V = ( pi × r ^2 × h ) /3

= (22 / 7 ) × ( 5.25 )^2 × 3 / 3

= 86.625 cubic cm

ii ) let the slant height of the cone = l cm

l^2 = r^2 + h^2

= 3^2 + ( 5.25 )^2

= 9 + 27.5625

= 36.5625

Therefore ,

l = 6.046 ( approx)

The area of the canvas required to from rain

= curved surface area of the cone

= pi × r × l

= (22/ 7 ) × 5.25 × 6.046

= 697.62 / 7

= 99.66 cm^2

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