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Question
A heap of wheat is in the form of a cone whose diameter is 10.5m and height is 3m. Find its volume. The heap is to be covered by canvas to protect it from rain. Find the area of the canvas required.
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Solution
r=10.5/2 m
h=3m
Volume of cone = 1/3 * pi * r^2 * h = 1/3 * 3.14 * 5.75 * 5.75 * 3 = 103.81 m3
CSA of cone = Pi * r * L
(L) = Sqrt ( r^2 + h^2) = sqrt( 5.75*5.75 + 3 * 3) = 6.48m
CSA = 3.14 * 5.75 * 6.48 = 117.1 m2
Area of canvas required = 117.1 m2
h=3m
Volume of cone = 1/3 * pi * r^2 * h = 1/3 * 3.14 * 5.75 * 5.75 * 3 = 103.81 m3
CSA of cone = Pi * r * L
(L) = Sqrt ( r^2 + h^2) = sqrt( 5.75*5.75 + 3 * 3) = 6.48m
CSA = 3.14 * 5.75 * 6.48 = 117.1 m2
Area of canvas required = 117.1 m2
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