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Question

A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. The heap is to be covered by canvas to protect it from the rain. Find the volume of the heap and the area of the canvas required.

A
86.625 m3, 99.825 m2
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B
99.625 m3, 86.825 m2
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C
99.625 m3, 56.825 m2
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D
26.625 m3, 86.825 m2
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Solution

The correct option is A 86.625 m3, 99.825 m2
Radius (r) of the heap =(10.52)m=5.25 m
Height (h) of heap = 3 m
Volume of the heap =13πr2h
=(13×227×(5.25)2×3)m3
=86.625 m3
Therefore, the volume of the heap of wheat is 86.625 m3.
Area of canvas required = CSA of cone
=πrl=πrr2+h2
=[227×5.25×(5.25)2+(3)2]m2
=(227×5.25×6.05)m2
=99.825 m2
Therefore 99.825 m2 of canvas will be required to protect the heap from the rain.

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