A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. The heap is to be covered by canvas to protect it from the rain. Find the volume of the heap and the area of the canvas required.
A
86.625m3, 99.825m2
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B
99.625m3, 86.825m2
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C
99.625m3, 56.825m2
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D
26.625m3, 86.825m2
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Solution
The correct option is A86.625m3, 99.825m2 Radius (r) of the heap =(10.52)m=5.25m Height (h) of heap = 3 m Volume of the heap =13πr2h =(13×227×(5.25)2×3)m3 =86.625m3 Therefore, the volume of the heap of wheat is 86.625m3. Area of canvas required = CSA of cone =πrl=πr√r2+h2 =[227×5.25×√(5.25)2+(3)2]m2 =(227×5.25×6.05)m2 =99.825m2 Therefore 99.825m2 of canvas will be required to protect the heap from the rain.