A heat engine carries 1 mole of an ideal monoatomic gas around the cycle as shown in the figure, the amount of heat added in the process A to B and heat removed in the process C to A are:
A
qAB=450R and qCA=−450R
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B
qAB=450R and qCA=−225R
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C
qAB=375R and qCA=−250R
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D
qAB=375R and qCA=−450R
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Solution
The correct option is CqAB=375R and qCA=−250R Case I For process AB: △T=T2−T1=600−350=250K n=1 Cv=32R (for monoatomic gas) At constant volume heat absorbed is given as: △U=qv=nCv,m△T=32R×250=375R
Case II For process CA: △T=T2−T1=350−450=−100K n=1 Cp=52R (for monoatomic gas) At constant pressure heat removed is given as: △H=qp=nCp,m△T=52R(−100)=−250R