A heat engine works on a carnot cycle with a heat sink at a temperature of $2700 K .$ The efficiency of the engine is $10 %$ . Determine the temperature of heat source.

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Solution

Given,

Temperature of heat source, $T_{1} = 2700 K$

Efficiency of cycle, $η = 10$ %

Efficiency of Carnot engine,

$η = 1 - \frac{T_{2}}{T_{1}}$

$\Rightarrow \frac{10}{100} = 1 - {\frac{T_{2}}{2700}}^{'}$

$\Rightarrow T_{2} = 2430 K$

Hence, sink temperature is $2430 K$

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A heat engine works on a carnot cycle with a heat sink at a temperature of 2700 K. The efficiency of the engine is 10%. Determine the temperature of heat source.

Given, Temperature of heat source, T1=2700K Efficiency of cycle, η=10% Efficiency of Carnot engine, η=1−T2T1 ⇒10100=1−T22700′ ⇒T2=2430K Hence, sink temperature is 2430K

A heat engine works on a carnot cycle with a heat sink at a temperature of $2700 K .$ The efficiency of the engine is $10 %$ . Determine the temperature of heat source.

Given,

Temperature of heat source, $T_{1} = 2700 K$

Efficiency of cycle, $η = 10$ %

Efficiency of Carnot engine,

$η = 1 - \frac{T_{2}}{T_{1}}$

$\Rightarrow \frac{10}{100} = 1 - {\frac{T_{2}}{2700}}^{'}$

$\Rightarrow T_{2} = 2430 K$

Hence, sink temperature is $2430 K$