A heat flux of $4000$ J/s is to be passed through a copper rod of length $10$ cm and area of cross-section $100$ sq cm The thermal conductivity of copper is $400$ W/ mC.The two ends of this rod must be kept at a temperature difference of..

Open in App

Solution

$\frac{d q}{d t} = K A △ T / I$
$△ T = I / (K \times A) \times d q / d t = 0.1 / 400 \times 100 {\times 10}^{- 4} \times 4000 = 100^{0} C$

Suggest Corrections

Similar questions

Q. A heat flux of

4000 J/s

is to be passed through a copper rod of length

10 cm

and area of cross section

100 {cm}^{2}

. The thermal conductivity of copper is

400 {W/m}^{\circ} C

. The two ends of the rod must be kept at temperature difference of

Q. The ends of copper rod of length

1 m

and area of cross section

1 {cm}^{2}

are maintained at

0^{\circ} C

and

100^{\circ} C

. At the centre of the rod there is a source of heat of power

25 W

. Thermal conductivity of copper is

400 W/m-K

. In steady state, the temperature at the section of rod at which source is supplying heat, will be

The left end of a copper rod (length = 20 cm , area of cross section = 0.20 $c m^{2}$ ) is maintained at $20^{\circ} C$ and the rightend is maintained at $80^{\circ} C$ . Neglecting any loss of heat through radiation, find (a) the temperature at a point 11 cm from the left end and (b) the heat current through the rod. Thermal conductivity of copper = $385 W m^{- 1 \circ} C^{- 1}$ .