Question

A heat flux of $4000$ J/s is tobe passed through a copper rod of length $10cm$ and area of cross-section $100sq.cm$. The thermal conductivity of copper is $400W/mC$. The two ends of this rod must be kept at a temperature difference of

• A. $1^{\circ }C$
• B. ${10}^{\circ }C$
• C. ${100}^{\circ }C$
• D. ${1000}^{\circ }C$

Answer 1

The correct option is C ${100}^{\circ }C$

$\frac{dQ}{dt}=\frac{KA△T}{I}$

$△T=\frac{I}{KA}\ast \frac{dQ}{dt}=\frac{0.1}{400\ast 100\ast {10}^{-4}}\ast 4000={100}^{o}C$