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Question

A heat flux of 4000 J/s is to be passed through a copper rod of length 10 cm and area of cross section 100 cm2. The thermal conductivity of copper is 400 W/mC. The two ends of the rod must be kept at temperature difference of

A
1C
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B
10C
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C
100C
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D
1000C
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Solution

The correct option is C 100C
From conduction law,
Qt=KA(θ1θ2)L
4000=400×(100×104)×(θ1θ2)(10×102)
θ1θ2=100C
Hence, option (c) is the correct answer.

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