A heat flux of 4000J/s is to be passed through a copper rod of length 10cm and area of cross section 100cm2. The thermal conductivity of copper is 400W/m∘C. The two ends of the rod must be kept at temperature difference of
A
1∘C
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B
10∘C
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C
100∘C
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D
1000∘C
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Solution
The correct option is C100∘C From conduction law, Qt=KA(θ1−θ2)L ⇒4000=400×(100×10−4)×(θ1−θ2)(10×10−2) ⇒θ1−θ2=100∘C
Hence, option (c) is the correct answer.