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Question

A heater A gives out 300 W of heat when connected to a 200 V supply. A second heater B gives out 600 W when connected to a 200 V supply. If a series combination of the two heaters is connected to a 200 V supply, the heat output will be

A
100 W
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B
450 W
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C
300 W
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D
200 W
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Solution

The correct option is D 200 W
Power is defined as, P=V2R

R=V2P


RA=(200)2300=4003 Ω

And, RB=(200)2600=2003 Ω

Since, both are in series combination,

Req=RA+RB=200 Ω

So, power of combination will be

P=V2Req=(200)2200=200 W

So, option (d) is the right choice.

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