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Question
A heater coil is rated at 100w_200v.it is cut into two identical parts.both parts are connected together in parallel with same source of 200v .. calculate the energy liberated per second in new combination..
A heater coil is rated at 100w_200v.it is cut into two identical parts.both parts are connected together in parallel with same source of 200v .. calculate the energy liberated per second in new combination..
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Solution
power rating,m P = 100 W
voltage supply, V = 200V
thus resistance of the coil:
P = V2 / R
thus R = 40000/100 = 400 ohm
hence of the two new parts produced, new resistance of each part, R' = 200 ohm each
on parallel connection, net resistance:
1/Rt = 1/R' + 1/R'
hence Rt = R'/2 = 100 ohm
and the new power rating, P = V2 /Rt = 40000/100 = 400 W
voltage supply, V = 200V
thus resistance of the coil:
P = V2 / R
thus R = 40000/100 = 400 ohm
hence of the two new parts produced, new resistance of each part, R' = 200 ohm each
on parallel connection, net resistance:
1/Rt = 1/R' + 1/R'
hence Rt = R'/2 = 100 ohm
and the new power rating, P = V2 /Rt = 40000/100 = 400 W
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