Given: The initial current drawn is 3.2 A, the supply voltage is 230 V, the steady state value of the current is 2.8 A, the room temperature is 27°C and the temperature coefficient is 1.70× 10 −4 ° C −1 .
The initial resistance is given as,
R 1 = V I 1
Where, the supply voltage is V, the initial current drawn is I 1 and the resistance is R 1 .
By substituting the given values in the above equation, we get
R 1 = 230 3.2 =71.87 Ω
The resistance at steady state is given as,
R 2 = V I 2
Where, the supply voltage is V, the current at steady state is I 2 and the resistance at steady state is R 2 .
By substituting the given values in the above formula, we get
R 2 = 230 2.8 =82.14 Ω
The temperature coefficient is given as,
α= R 2 − R 1 R 1 ( T 2 − T 1 )
Where, the steady state temperature is T 2 , the room temperature is T 1 and the temperature coefficient is α.
By substituting the given values in the above formula, we get
1.7× 10 −4 = 82.14−71.87 71.87×( T 2 −27°C ) T 2 =840.5+27 =867.5 °C
Thus, the steady state temperature of the heating element is 867.5°C.