A heavenly body of mass m revolves around a planet of mass M in a circular orbit with a constant speed v. The radius of the orbit is given by

\frac{G M}{v^{2}}

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\frac{m v^{2}}{G M}

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\frac{G M}{v^{3}}

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\frac{v^{2}}{G M}

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Solution

The correct option is A $\frac{G M}{v^{2}}$
$\frac{G M m}{r^{2}} = \frac{m v^{2}}{r}$
$\Rightarrow r = \frac{G M}{v^{2}}$
Hence,
option $(A)$ is correct answer.

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A heavenly body of mass m revolves around a planet of mass M in a circular orbit with a constant speed v. The radius of the orbit is given by

The correct option is A GMv2GMmr2=mv2r⇒r=GMv2Hence,option (A) is correct answer.

The correct option is A $\frac{G M}{v^{2}}$
$\frac{G M m}{r^{2}} = \frac{m v^{2}}{r}$
$\Rightarrow r = \frac{G M}{v^{2}}$
Hence,
option $(A)$ is correct answer.