Question

A heavy block of mass m is slowly placed on a conveyor belt moving with speed v. If coefficient of friction between block and the belt is $\mu$, the block will slide on the belt through distance ____

• A. $\frac{v}{\mu g}$
• B. $\frac{v^2}{\sqrt{\mu g}}$
• C. ${\left(\frac{v}{\mu g}\right)}^2$
• D. $\frac{v^2}{2\mu g}$

Answer 1

The correct option is D $\frac{v^2}{2\mu g}$

$F=ma=\mu mg\Rightarrow a=\mu g$

$v^2=u^2+2as[\because u=0]$

$v^2=2\left(\mu g\right)s$

$\therefore s=\frac{v^2}{2\mu g}$