Question

A heavy nucleus having a mass number $200$ gets disintegrated into two small fragments of mass numbers $80$ and $120$. If binding energy per nucleon for perent atom is $6.5$ MeV and for daughter nuclei is $7$ MeV and $8$ MeV respectively, then the energy released in the decay will be :

• A. $200MeV$
• B. $-220MeV$
• C. $220MeV$
• D. $180MeV$

Answer 1

The correct option is C $220MeV$

${}^{200}X{\to }^{120}Y{+}^{80}Z$

Energy released $=$ Nuclear Energy of Products $-$ Nuclear energy of reactants

$=120\times 8+80\times 7-200\times 6.5=220MeV$