Question

A heavy nucleus having mass number $200$ gets disintegrated into two small fragments of mass number $80$ and $120$. If binding energy per nucleon for parent atom is $6.5MeV$ and for daughter nuclei is $7MeV$ and $8MeV$ respectively, then the energy released in the decay will be:

• A. $200MeV$
• B. $-220MeV$
• C. $220MeV$
• D. $180MeV$

Answer 1

The correct option is C $220MeV$

${}^{200}X⟶{}^{80}Y+{}^{120}Z$
Binding energy of parent atom $=200\times 6.5MeV$
Binding energy of daughter nuclei $=(80\times 7+120\times 8)MeV$

Energy released = (Binding energy of daughter nuclei - Binding energy of parent atom)
$=(80\times 7+120\times 8-200\times 6.5)$
$=220MeV$