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Standard XII

Physics

Mass Energy Equivalence

A heavy nucle...

Question

A heavy nucleus $X$ of mass number $240$ and binding energy per nucleon $7.6 M e$ is split into two fragment $Y$ and $Z$ of mass numbers $110$ and $130$ . The binding energy per nucleon in $Y$ and $Z$ is $8.5 M e V$ per nucleon. Calculate the energy $Q$ released per fission in $M e V$ .

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Solution

Energy released per nucleon is $Q = b i n d i n g e n e r g y o f p r o d u c t s - b i n d i n g e n e r g y o f r e a c t a n t s$

Here X splits into Y and Z.

So, $Q = (M_{Y} + M_{Z}) c^{2} - M_{X} c^{2}$

$Q = (110 + 130) 8.5 - 240 \times 7.6$

$Q = (240 \times 8.5) - 1824$

$Q = 216 M e v$

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Similar questions

Q. A heavy nucleus

X

of mass number

240

and binding energy per nucleon

7.6 M e V

is split into two fragments

Y

and

Z

of mass numbers

110

and

130

the binding energy of nucleons in

Y

8.5 M e V

per nucleon

.

Calculate the energy

Q

released per fission in

M e V .

Q. Graph of binding energy per nucleon

(\frac{B}{A}) v s

mass number (A) is given.

x

, a hypothetical nucleus with mass number A=230 splits into 2 nucleus with mass number 60 and 170. Find energy released in this fission in meV

Q. A nucleus with mass number

240

breaks into two fragments, each of mass number

120

. The binding energy per nucleon of unfragmented nuclei is

7.6 MeV

while that of fragments is

8.5 MeV .

Energy released in the process is

Q. A heavy nucleus having a mass number

200

gets disintegrated into two small fragments of mass numbers

80

and

120

. If binding energy per nucleon for perent atom is

6.5

MeV and for daughter nuclei is

7

MeV and

8

MeV respectively, then the energy released in the decay will be :

Q. Binding Energy per nucleon of a fixed nucleus

X^{4}

6 M e V .

It absorbs a neutron moving with

K E = 2 M e V,

and converts into

Y

at ground state, emitting a photon of energy

1 M e V .

The Binding Energy per nucleon of

Y

(

i n M e v

) is:

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A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6Me is split into two fragment Y and Z of mass numbers 110 and 130. The binding energy per nucleon in Y and Z is 8.5MeV per nucleon. Calculate the energy Q released per fission in MeV.

Energy released per nucleon is Q=bindingenergyofproducts−bindingenergyofreactants Here X splits into Y and Z. So, Q=(MY+MZ)c2−MXc2 Q=(110+130)8.5−240×7.6 Q=(240×8.5)−1824 Q=216Mev

A heavy nucleus $X$ of mass number $240$ and binding energy per nucleon $7.6 M e$ is split into two fragment $Y$ and $Z$ of mass numbers $110$ and $130$ . The binding energy per nucleon in $Y$ and $Z$ is $8.5 M e V$ per nucleon. Calculate the energy $Q$ released per fission in $M e V$ .

Energy released per nucleon is $Q = b i n d i n g e n e r g y o f p r o d u c t s - b i n d i n g e n e r g y o f r e a c t a n t s$

Here X splits into Y and Z.

So, $Q = (M_{Y} + M_{Z}) c^{2} - M_{X} c^{2}$

$Q = (110 + 130) 8.5 - 240 \times 7.6$

$Q = (240 \times 8.5) - 1824$

$Q = 216 M e v$