Question

A heavy nucleus $X$ of mass number $240$ and binding energy per nucleon $7.6MeV$ is split into two fragments $Y$ and $Z$ of mass numbers $110$ and $130$ the binding energy of nucleons in $Y$ is $8.5MeV$ per nucleon$.$ Calculate the energy $Q$ released per fission in $MeV.$

• A. 240$Mev$
• B. 216$Mev$
• C. 120$Mev$
• D. 108$Mev$

Answer 1

The correct option is B 216$Mev$

The nuclear reaction is

$X^{240}\to Y^{110}+Z^{130}+Q$

As per given data

$Q=110\times 8.5+130\times 8.5-240\times 7.6$

$=240\left(0.9\right)MeV=216MeV$

Hence,

option $\left(B\right)$ is correct answer.