CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

1st Equation of Motion

a heavy parti...

Question

a heavy particle is suspended by a 1.5 metre long string. it is given a horizontal velocity of57m/s.(a) find the angle made by the string with the upward vertical when it becomes slack(b) find the speed of the particle at this instant(c) find the maximum height reached by the particle over the point of suspensionTake g=10m/s2

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. A heavy particle is suspended by a 1⋅5 m long string. It is given a horizontal velocity of

\sqrt{57} m / s

. (a) Find the angle made by the string with the upward vertical when it becomes slack. (b) Find the speed of the particle at this instant. (c) Find the maximum height reached by the particle over the point of suspension. Take g = 10 m/s².

Q. A heavy particle is suspended by a string of length l. The particle is given a horizontal velocity

v_{0}

. The string becomes slack at some angle and the particle proceeds on a parabola. Find the value of

v_{0}

if the particle passes through the point of suspension.

Q. A heavy particle hangs from a point O, by a string of length a. It is projected horizontally with a velocity

v = \sqrt{(2 + \sqrt{3}) a g}

.
The angle with the upward vertical, string makes where string becomes slack is

Q. A particle is suspended from a fixed point by a string of length

5 m

. It is projected from the equilibrium position with such a velocity that the string becomes slack after the particle has reached a height of

8 m

above the lowest point. Find the velocity of the particle, just before the string becomes slack.(take

g = 10 {m/s}^{2}

)

Q. A particle is suspended from a fixed point by a string of length

5 m

. It is projected from the equilibrium position with such a velocity that the string becomes slack after the particle has reached a height of

8 m

above the lowest point. Find the velocity of the particle, just before the string becomes slack.(take

g = 10 {m/s}^{2}

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Motion Under Constant Acceleration

PHYSICS

Watch in App

explore_more_icon

Explore more

1st Equation of Motion

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon