Question

A heavy piece of machinery is raised by sliding it a distance of $d=10\text{m}$ along a plank oriented at an angle, $\theta ={60}^{\circ }$ as shown in figure. How far has it moved vertically and horizontally?

Answer 1

Using simple trigonometry,

$x\text{component}=10\cos {60}^{\circ }=10\times \frac{1}{2}=5\text{m}$

$y\text{component}=10\sin {60}^{\circ }=10\times \frac{\sqrt{3}}{2}=8.66\text{m}$

Hence, option $\left(\text{C}\right)$ is the correct answer.