A heavy piece of machinery is raised by sliding it a distance of d-10m along a plank oriented at an angle- - 60- as shown in figure- How far has it moved vertically and horizontally-

Using simple trigonometry x component = 10 cos 60^∘ = 10 × 1/2 = 5m y component = 10 sin 60^∘ = 10 × √(3)/2 = 8.66 m ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Vector Component

A heavy piece...

Question

A heavy piece of machinery is raised by sliding it a distance of d=10m along a plank oriented at an angle, $θ = 60^{\circ}$ as shown in figure. How far has it moved vertically and horizontally?

x- 8.66m, y- 5m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x - 5m, y- 9m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x-5m, y-8.66m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x-4.5m, y-8.66m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
x-5m, y-8.66m

Using simple trigonometry

$x c o m p o n e n t = 10 c o s 60^{\circ} = 10 \times \frac{1}{2} = 5 m$

$y c o m p o n e n t = 10 s i n 60^{\circ} = 10 \times \frac{\sqrt{3}}{2} = 8.66 m$

Suggest Corrections

Similar questions

A heavy piece of machinery is raised by sliding it a distance of d=10m along a plank oriented at an angle, $θ = 60^{\circ}$ as shown in figure. How far has it moved vertically and horizontally?

Q. Inside a lift moving vertically downwards with an acceleration

g

, two blocks of mass

m

and

2 m

are placed as shown in the figure. The top block is given a sharp hit at an angle

θ

so as to move it. What is the value of

θ

for which both blocks move together without sliding on each other?

Q. A small body is projected up a rough

(μ = \frac{1}{2})

inclined plane

(θ = 60^{\circ})

with a speed of

v = 10 m / s

as shown. How far along the plane it moves up before coming to rest? (Take

g = 10 m / s^{2}

)

Q. The figure shows a pendulum of length

^{'} I^{'}

suspended at a distance

x

vertically above a peg. The pendulum bob is deflected through an angle

θ

and then released. When

θ = 90^{\circ}

, the pendulum complete the circle. When

θ = 60^{\circ}

the velocity of the bob as it passes position

E

\sqrt{k l}

. Find the value of

k (g = 10 m / s e c^{2})

Q. A heavy & big sphere is hang with a string of length

ℓ

, this sphere moves in a horizontal circular path making an angle

θ

with vertical then its time period is:

Join BYJU'S Learning Program

A heavy piece of machinery is raised by sliding it a distance of d=10m along a plank oriented at an angle, θ=60∘ as shown in figure. How far has it moved vertically and horizontally?

The correct option is C x-5m, y-8.66m Using simple trigonometry xcomponent=10cos60∘=10×12=5m ycomponent=10sin60∘=10×√32=8.66m

A heavy piece of machinery is raised by sliding it a distance of d=10m along a plank oriented at an angle, $θ = 60^{\circ}$ as shown in figure. How far has it moved vertically and horizontally?

The correct option is C
x-5m, y-8.66m

Using simple trigonometry

$x c o m p o n e n t = 10 c o s 60^{\circ} = 10 \times \frac{1}{2} = 5 m$

$y c o m p o n e n t = 10 s i n 60^{\circ} = 10 \times \frac{\sqrt{3}}{2} = 8.66 m$