A heavy trolley is moving horizontally with a velocity of v m/s w.r.t. earth. A man starts running from one end of the trolley with a velocity 1.5v m/s w.r.t. the trolley. After reaching the opposite end, the man turns back and continues running with a velocity of 1.5v m/s w.r.t. trolley in the backward direction. If the length of trolley is L then the maximum displacement of the man with respect to earth will be

2.5 L

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1.5 L

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\frac{5 L}{3}

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Solution

The correct option is C $\frac{5 L}{3}$
$V_{m G} = 2.5 v$
$V_{T G} = v$
Time to reach opposite end $= \frac{L}{1.5 v}$
Maximum displacement w.r.t. ground $= \frac{L}{1.5 v} \times 2.5 v = \frac{5}{3} L$

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