A heavy uniform chain lies on a horizontal table top. If the coefficient of friction between the chain and the table surface is 0.25, then the maximum fraction of length of chain that can overhang on the edge of the table is
A
0.20
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B
0.35
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C
0.25
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D
0.15
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Solution
The correct option is A0.20 The given situation can be considered as shown
Let x be the length of the chain hanging, L be the total length of the chain and mass of total chain be m ∴ mass of x length of the chain will be xm and the mass of (L−x) length of the chain will be (L−x)m So, FBD can be considered as
From the FBD we get ⇒T=xmg and, N=(L−x)mg Also, T=f=μN ⇒T=0.25(L−x)mg ⇒xmg=0.25(L−x)mg ⇒L−x=4x ⇒x=L5 Thus, fraction of chain that can hung is xL=L/5L=0.2