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Question

A heavy uniform chain lies on a horizontal top of table. If the coefficient of friction between the chain and the table is 0.25 then the maximum percentage of the length of the chain that can hang over one edge of the table is:

A
20 %
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B
25 %
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C
35 %
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D
15 %
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Solution

The correct option is A 20 %
Let the length of total chain be l
The part which is lying on the table be x and lying outside be y
In equilibrium , the frictional force must balance the tension force
Let us take t as weight per unit length and n as coefficient of friction
We get ntx=ty
nx=y
Here we need to find yl
yl=yx+y=nn+1
Given n=0.25
So we get yl=0.251+0.25=15
Therefore the maximum percentage of chain hanging is 15×100=20%
Therefore option A is correct

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