A helicopter is flying at 3564m above ground- If an angle of 30 - is subtended at a ground point by the helicopter position 100s apart- what is the speed of the helicopter-

The correct option is C 20m s ^ 1 tan30= x 3564 ⇒ V= x t = 3564 #160;tan(30) 100 =20m/s ...

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Standard XII

Physics

1st Equation of Motion

A helicopter ...

Question

A helicopter is flying at $3564 m$ above ground. If an angle of $30^{\circ}$ is subtended at a ground point by the helicopter position $100 s$ apart, what is the speed of the helicopter?

100 m s^{- 1}

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150 m s^{- 1}

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20 m s^{- 1}

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25 m s^{- 1}

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Solution

The correct option is C $20 m s^{- 1}$
$t a n 30 = \frac{x}{3564} \Rightarrow V = \frac{x}{t} = \frac{3564 t a n (30)}{100} = 20 m / s$

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A helicopter is flying at 3564m above ground. If an angle of 30∘ is subtended at a ground point by the helicopter position 100s apart, what is the speed of the helicopter?

The correct option is C 20ms−1tan30=x3564⇒V=xt=3564tan(30)100=20m/s

A helicopter is flying at $3564 m$ above ground. If an angle of $30^{\circ}$ is subtended at a ground point by the helicopter position $100 s$ apart, what is the speed of the helicopter?

The correct option is C $20 m s^{- 1}$
$t a n 30 = \frac{x}{3564} \Rightarrow V = \frac{x}{t} = \frac{3564 t a n (30)}{100} = 20 m / s$