A helicopter is flying at a height of $500 m$ . If all of sudden its engines stops working, the helicopter will fall on the earth in

10

seconds

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12

seconds

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15

seconds

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20

seconds

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Solution

The correct option is A $10$ seconds
Using equation of motion
$s = u t + \frac{1}{2} a t^{2}$
$\Rightarrow 500 = 0 + \frac{1}{2} \cdot g \cdot t^{2}$
$\Rightarrow \frac{1000}{10} = t^{2}$ (where $g = 10 m / s^{2}$ )
$\Rightarrow t = 10 s e c$

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A helicopter is flying at a height of 500 m. If all of sudden its engines stops working, the helicopter will fall on the earth in

The correct option is A 10 secondsUsing equation of motion s=ut+12at2 ⇒500=0+12⋅g⋅t2 ⇒100010=t2 (where g=10m/s2) ⇒t=10 sec

A helicopter is flying at a height of $500 m$ . If all of sudden its engines stops working, the helicopter will fall on the earth in

The correct option is A $10$ seconds
Using equation of motion
$s = u t + \frac{1}{2} a t^{2}$
$\Rightarrow 500 = 0 + \frac{1}{2} \cdot g \cdot t^{2}$
$\Rightarrow \frac{1000}{10} = t^{2}$ (where $g = 10 m / s^{2}$ )
$\Rightarrow t = 10 s e c$