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Question

A helicopter is flying horizontally at an altitude of 2 km with a speed of 100 msāˆ’1. A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is (g=10 msāˆ’2)

A
2 km
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B
0.2 km
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C
20 km
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D
4 km
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Solution

The correct option is A 2 km
Height of the helicopter from the ground =2000 m

Using second equation of motion,
h=uyt+12gt2
Since uy=0, t=2hg
t=2×200010 s=400 s=20 s
Horizontal distance travelled by the packet
x=ut=100 ms1×20 s=2000 m=2 km

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