A helicopter is flying horizontally at an altitude of 2km with a speed of 100msā1. A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is (g=10msā2)
A
2km
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B
0.2km
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C
20km
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D
4km
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Solution
The correct option is A2km Height of the helicopter from the ground =2000m
Using second equation of motion, h=uyt+12gt2
Since uy=0, t=√2hg ⇒t=√2×200010s=√400s=20s ∴ Horizontal distance travelled by the packet x=ut=100ms−1×20s=2000m=2km