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Byju's Answer
Standard IX
Physics
Derivation of Position-Time Relation by Graphical Method
A helicopter ...
Question
A helicopter is rising up with speed of 10m/s .A packet is dropped from helicopter when it is 495 m above the ground .Cakculate with what velocity and after how long will the packet hit the ground ? What will be the height of helicopter at that time?
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Solution
Dear Student,
u
=
10
m
/
s
,
h
=
495
m
f
r
o
m
s
i
g
n
c
o
n
v
e
n
t
i
o
n
t
a
k
e
u
p
w
a
r
d
a
s
+
v
e
a
n
d
d
o
w
n
w
a
r
d
a
s
-
v
e
u
=
10
m
/
s
,
h
=
-
495
m
,
a
=
-
g
l
e
t
t
h
e
v
e
l
o
c
i
t
y
b
e
v
a
t
t
h
e
g
r
o
u
n
d
v
=
-
100
+
2
*
10
*
495
=
-
100
m
/
s
-
v
e
s
h
o
w
d
o
w
n
w
a
r
d
t
i
m
e
t
a
k
e
n
b
e
t
t
=
v
-
u
a
=
-
100
-
10
-
10
=
11
s
e
c
h
e
l
i
c
o
p
t
e
r
r
i
s
e
f
u
r
h
t
e
r
i
n
11
s
e
c
H
=
495
+
10
*
11
=
495
+
110
=
605
m
R
e
g
a
r
d
s
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