A helium atom, a hydrogen atom and a neutron have masses of $4.003 u$ , $1.008 u$ and $1.009 u$ (unified atomic mass units), respectively. Assuming that hydrogen atoms and neutrons can fuse to form helium, what is the binding energy of a helium nucleus?

2.01 u

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3.031 u

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1.017 u

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0.031 u

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Solution

The correct option is D $0.031 u$
$2_{1} H^{1} + 2 n \to_{2} H e^{4}$
Binding energy $=$ Mass defect
$= - m_{H e} + 2 m_{n} + 2 m_{H}$
$= 2 (1.008) + 2 (1.009) - 4.003$
$= 0.031 u$

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Similar questions

Q. The masses of neutron and proton are

1.0087

and

1.0073

amu respectively. If the neutrons and protons combine to form a Helium nucleus of mass

4.0015 a m u

, the binding energy of the Helium nucleus will be :

Q. In a nuclear fusion reaction hydrogen atoms combine to create a helium atom. But in a hydrogen atom there are no neutrons, then where does the neutrons in helium nucleus come from ?

Q. The mass of the proton is 1.0073 u and that of the neutron is 1.0087 u ( u = atomic mass unit). The binding energy of

_{2}^{4} H e

is :

Given, mass of helium nucleus ≈ 4.0015u

Q. The masses of neutron and proton are

1.0087 a . m . u .

and

1.0073 a . m . u .

respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass

4.0015 a . m . u

, then the binding energy fo the helium nucleus will be: (

1 a . m . u . = 931 M e V

)

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

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A helium atom, a hydrogen atom and a neutron have masses of 4.003u, 1.008u and 1.009u (unified atomic mass units), respectively. Assuming that hydrogen atoms and neutrons can fuse to form helium, what is the binding energy of a helium nucleus?

The correct option is D 0.031u21H1+2n→2He4Binding energy = Mass defect =−mHe+2mn+2mH =2(1.008)+2(1.009)−4.003 =0.031u

A helium atom, a hydrogen atom and a neutron have masses of $4.003 u$ , $1.008 u$ and $1.009 u$ (unified atomic mass units), respectively. Assuming that hydrogen atoms and neutrons can fuse to form helium, what is the binding energy of a helium nucleus?

The correct option is D $0.031 u$
$2_{1} H^{1} + 2 n \to_{2} H e^{4}$
Binding energy $=$ Mass defect
$= - m_{H e} + 2 m_{n} + 2 m_{H}$
$= 2 (1.008) + 2 (1.009) - 4.003$
$= 0.031 u$