A hemisphere bowl is made of steel, $0.25 c m$ thick. the inner radius of the bowl is $5 c m$ . Find the outer curved surface area of the bowl.

Open in App

Solution

Given, Inner radius $= 5 c m$
Outer radius $= (5 + 0.25) c m = 5.25 c m$
Outer curved surface area
$= 2 \times π \times (5.25)^{2} = 173.25 m^{2}$

Suggest Corrections

Similar questions

Q. A hemispherical bowl is made of steel,

0.25 c m

thick. The inner radius of the bowl is

5 c m

. Find the outer curved surface area of the bowl.

Question 8
A hemispherical bowl is made of steel, 0.25 cm thick.The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl. $[A s s u m e π = \frac{22}{7}]$

A hemispherical bowl is made of steel, 0.25 cm thick.The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl. $[A s s u m e π = \frac{22}{7}]$

Q. A hemispherical bowl is made of brass,

0.25 c m

thickness. The inner radius of the bowl is

5 c m

. Find the ratio of outer surface area to inner surface area.

Q. Hemispherical bowl is made of steel 0.25 cm thick. Inner radius of bowl is 5 cmfind outer CSA .

Join BYJU'S Learning Program

A hemisphere bowl is made of steel, 0.25 cm thick. the inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Given, Inner radius =5 cmOuter radius =(5+0.25) cm=5.25 cmOuter curved surface area=2×π×(5.25)2=173.25 m2

A hemisphere bowl is made of steel, $0.25 c m$ thick. the inner radius of the bowl is $5 c m$ . Find the outer curved surface area of the bowl.

Given, Inner radius $= 5 c m$
Outer radius $= (5 + 0.25) c m = 5.25 c m$
Outer curved surface area
$= 2 \times π \times (5.25)^{2} = 173.25 m^{2}$