Question

A hemisphere of lead of radius $12cm$ is melted and cast into a right circular cone of height $54cm$. Find the radius of the base of the cone.

Answer 1

volume of hemisphere =volume of right circular cone

We have $2/3\pi R^3=1/3\pi r^{2}h$, substituting the values $R=12cm$ and $h=54cm$ in the above equation we get radius of the base of the cone $r=8cm$