Question

A hemisphere of lead of radius 6 cm is cast into a right circular cone of height 75cm.The radius of base of cone.

Answer 1

Let the radius of the cone be room

$\frac{1}{3}\times \pi \times R^2\times 75cm=\frac{2}{3}\pi \times 6\times 6\times 6$

$\Rightarrow R^2=\frac{2\times 6\times 6\times 6}{75}$

$R=\sqrt{\frac{2\times 6\times 6\times 6}{75}}$

$=\frac{12}{5}=2.4cm$