A hemispherical bowl fits exactly on the open surface of a cone with height 5 cm and radius 3.5 cm.What is the volume of the solid formed?
154 cm3
Given,
Radius of the cone = Radius of the hemisphere = r = 3.5 cm
Height of the cone, h = 5 cm
Total volume of the solid = Volume of the cone + Volume of the hemisphere
=13πr2h+23πr3
=(13×227×3.52×5)+(23×227×3.53)
=13×227×3.52(5+7)
=13×227×3.52×12
= 154 cm3