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Question

A hemispherical bowl fits exactly on the open surface of a cone with height 5 cm and radius 3.5 cm.What is the volume of the solid formed?


A

144 cm3

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B

132 cm3

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C

154 cm3

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D

169 cm3

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Solution

The correct option is C

154 cm3


Given,

Radius of the cone = Radius of the hemisphere = r = 3.5 cm

Height of the cone, h = 5 cm

Total volume of the solid = Volume of the cone + Volume of the hemisphere

=13πr2h+23πr3

=(13×227×3.52×5)+(23×227×3.53)

=13×227×3.52(5+7)

=13×227×3.52×12

= 154 cm3


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