Question

A hemispherical bowl has a radius of $3.5cm.$ What would be the volume of water it would contain?

Answer 1

The volume of a hemisphere of radius $r$ is given by $\frac{2}{3}\pi r^3.$

So, by using above formula,

$\begin{array}{cc}V& =\frac{2}{3}\pi r^3\\ & =\frac{2}{3}\times \frac{22}{7}\times 3.5\times 3.5\times 3.5\\ & =89.8c{m}^3\end{array}$

So, the volume of water hemisphere can store is equal to hemisphere $89.8c{m}^3.$