Question

A hemispherical bowl has inner radius $5cm$ and outer radius $6cm$. What will be the volume of solid enclosed between the two hemispheres? (Correct upto 2 decimal places)

• A. $904.78{cm}^3$
• B. $523.60{cm}^3$
• C. $381.18{cm}^3$
• D. $190.59{cm}^3$

Answer 1

The correct option is D $190.59{cm}^3$

The volume of hemispherical shell$=\frac{2}{3}\ast \pi \ast R^3-\frac{2}{3}\ast \pi \ast r^3$
where R and r are the outer and inner radius of the hemisphere
On solving the equation we get Volume$=190.59{cm}^3$