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Question

# A hemispherical bowl just floats without sinking in a liquid of density 1.2×103kg/m3. If the outer diameter and the density of the bowl are 1m and 2×104kg/m3 respectively, then the inner diameter of the bowl will be :

A
1.91 m
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B
0.5 m
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C
0.98 m
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D
1.75 m
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Solution

## The correct option is D 0.98 mTotal up trust force executed on the Bowl=23π(1m23)×1.2×103g=0.8π8103g=0.1π×103...................1Now,For bowl to just float 1 should be equal to weight of bowl,So, Volume of bowl==0.2π×103×32×104m3=(13−r3)r3=18−0.2×3×1034×10r3==0.065r=0.982mSo,Inner Diameter=0.98m

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