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Question

A hemispherical bowl made of brass has inner radius of 3.5 cm. Find the cost of tin-plating the inner part of the bowl as well as tin plating a plate that exactly fits as a lid on bowl. Tin plating is done at the rate of Rs.10 per 100 sq.cm. [4 MARKS]

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Solution

Concept: 1 Mark
Formula: 1 Mark
Application: 2 Marks

Surface area that has to be plated = Curved surface area of the hemisphere bowl + surface area of the plate

=2πr2+πr2

=2×227×3.52+227×3.52

=3×227×3.52

=115.5cm2

Hence cost of tin plating

=115.5×10100

=Rs.11.55


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