A hemispherical bowl of internal diameter $36$ $c m$ contains a liquid.This liquid is to be filled in cylindrical bottles of radius $3$ $c m$ and height $6$ $c m .$ How many bottles are required to empty the bowl?

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Solution

$V o l u m e o f h e m i s p h e r i c a l b o w l = (\frac{2}{3}) π r^{3} = (\frac{2}{3}) \times (\frac{22}{7}) \times (\frac{18}{100})^{3} m^{3} = 0.01221 m^{3} V o l u m e o f 1 c y l i n d e r = π r^{2} h = (\frac{22}{7}) \times (\frac{3}{100})^{3} \times (\frac{6}{100}) = 0.0001697 m^{3} ∴ n u m b e r o f b o t t l e s r e q u i r e d = (\frac{0.01221}{0.0001697}) = 71.95 \approx 72 b o t t l e s .$

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