A hemispherical bowl of internal radius 9 cm is full of liquid. This liquid is to be filled into conical shaped small containers each of diameter 3 cm and height 4 cm. How many containers are necessary to empty the bowl?

Open in App

Solution

Bowl: Internal radius = 9 cm

Cone: radius = 1.5 cm , Height = 4 cm

$\frac{2}{3} \times π \times 9^{3} = n \times \frac{1}{3} π \times {1.5}^{2} \times 4$

n = $\frac{9 \times 9 \times 9}{2 \times 1.5 \times 1.5}$ = 162

$\\$

Suggest Corrections

Similar questions

Q. A hemispherical bowl of internal radius

9 c m

is full of liquid. This liquid is to be filled into a cylindrical shaped small bottle each of diameter

3 c m

and height

4 c m

. How many bottles are necessary to empty the bowl.

A hemispherical bowl of internal radius 9 cm is full of liquid. The liquid is to be filled into cylindrical shaped small bottles, each of diameter 3 cm and height 4 cm. How many bottles are needed to empty the bowl?

Join BYJU'S Learning Program

A hemispherical bowl of internal radius 9 cm is full of liquid. This liquid is to be filled into conical shaped small containers each of diameter 3 cm and height 4 cm. How many containers are necessary to empty the bowl?

Bowl: Internal radius = 9 cm Cone: radius = 1.5 cm ​​​​​​​​​​​​​​, Height = 4 cm ​​​​​​​ 23 × π × 93=n×13π×1.52×4 n =9 × 9 × 92 × 1.5 × 1.5 = 162 ​​​​​​​

Bowl: Internal radius = 9 cm

Cone: radius = 1.5 cm , Height = 4 cm

$\frac{2}{3} \times π \times 9^{3} = n \times \frac{1}{3} π \times {1.5}^{2} \times 4$

n = $\frac{9 \times 9 \times 9}{2 \times 1.5 \times 1.5}$ = 162

$\\$