A hemispherical surface of radius $R = 20 m m$ . Find the image distance (in mm) of a point object on the axis of the rod, $80 m m$ to the left of the vertex. The rod is in air.
120

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Solution

The correct option is A 120
Given:
$μ_{1} = 1$
$μ_{2} = 1.5$
$R = + 20 m m$
$u = - 80 m m$

Equation of refraction of light at curved surfaces is given as:
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
$\frac{1.5}{v} - \frac{1}{- 80} = \frac{1.5 - 1}{20}$
$v^{'} = + 120 m m$
The image is formed at distance of $120 m m$ and is hence, real.

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A hemispherical surface of radius R=20mm. Find the image distance (in mm) of a point object on the axis of the rod, 80mm to the left of the vertex. The rod is in air.120

The correct option is A 120Given: μ1=1 μ2=1.5 R=+20mm u=−80mm Equation of refraction of light at curved surfaces is given as: μ2v−μ1u=μ2−μ1R 1.5v−1−80=1.5−120 v′=+120 mm The image is formed at distance of 120mm and is hence, real.

A hemispherical surface of radius $R = 20 m m$ . Find the image distance (in mm) of a point object on the axis of the rod, $80 m m$ to the left of the vertex. The rod is in air.
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