Question

A hemispherical tank is made up of an iron sheet $1$ cm thick. If the inner radius is $1$ m, then find the volume of the iron used to make the tank.

Answer 1

Given:

$\Rightarrow$Inner radius $r_l=1$m$=r_1$

$\Rightarrow$Thickness $=1$cm$=0.01$m

$\Rightarrow$Outer radius $=1+0.01=1.01$m$=r_0$

$\Rightarrow$Volume of iron used

$=\frac{2}{3}\pi (r_0^2-r_l^2)$

$=\frac{2}{3}\times \frac{22}{7}\times ({\left(1.01\right)}^3-{\left(1\right)}^3)$

$=0.0634$cm${}^3$