CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A heterozygous pea plant, that is tall with yellow seeds (TtYy), is allowed to self-fertilize. Which of the following will have the maximum identical genotypic combinations?

A
TtYY
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
TTYy
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
TtYy
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Ttyy
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C TtYy
Cross between individuals differing in two observed traits is called dihybrid cross.
In the question, a heterozygous pea plant with tall and yellow seeds (TtYy) is self fertilised. This is similar to the selfing of F1 generation in Mendel's dihybrid experiment, which gives rise to the F2generation with a phenotypic ratio of 9:3:3:1. Although the sixteen progeny have four phenotypes, their genetic composition is quite diverse and different. The genotypic ratio is 1:2:1:2:4:2:1:2:1.
In the progeny of sixteen, 4 progenies have an identical genetic composition (YyRr).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon