A hockey ball at rest is hit by a stick such that the force acts on the ball for 15 seconds.If the mass of ball is 100 grams and it covers a distance of 100m in 2 seconds. Find the force applied by the hockey stick?

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Solution

Velocity of the ball after withdrawing the force is
$v = \frac{100}{2} = 50 {ms}^{- 1}$
So the acceleration of the ball is
$a = \frac{50 - 0}{15} = 3.33 {ms}^{- 2}$
So the applied force is
$F = m a = 0.1 \times 3.33 = 0.33 N$

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A hockey ball at rest is hit by a stick such that the force acts on the ball for 15 seconds.If the mass of ball is 100 grams and it covers a distance of 100m in 2 seconds. Find the force applied by the hockey stick?

Velocity of the ball after withdrawing the force is v=1002=50 ms-1 So the acceleration of the ball is a=50-015=3.33 ms-2 So the applied force is F=ma=0.1×3.33=0.33 N

Velocity of the ball after withdrawing the force is
$v = \frac{100}{2} = 50 {ms}^{- 1}$
So the acceleration of the ball is
$a = \frac{50 - 0}{15} = 3.33 {ms}^{- 2}$
So the applied force is
$F = m a = 0.1 \times 3.33 = 0.33 N$